RP / I / GAA

[fierceness]

just a side note, according to

Post 468813

(Rhodium: "Final Word on the HI/RP Mechanism", Stimulants) PI3 is not formed but rather P2I4

[WizardX]

fierceness stated:

according to Rhodium: "Final Word on the HI/RP Mechanism" (Stimulants) PI3 is not formed but rather P2I4

diphosphorous tetraiodide, P2I4 is formed because the ratio of P to I2 is basically 2:2 or cancelled down to the lowest denomination, 1:1

This results from HI/RP and the liberated I2 comes from HI dissociation (2HI => I2 + H2) and from iodoephedrine + HI => meth + I2

2 P + 2 I2 ==> P2I4


The elemental combination of P + I2 will give the PI3 and, this will predominate.

2 P + 3 I2 = 2 PI3

PI3 + 3 HOH = 3HI + H3PO3

[Organikum]

So it is right:

Phosphorus and iodine in GAA (anhydrous conditions) will form PI3 which will iodinate an benzylic alcohol so one is present?