klassasin
June 4th, 2003, 08:52 PM
This was written to explain how to write and solve stoichiometric ratios. For my example I will use the synthesis of HNO3 using H2SO4 and a nitrate (KNO3).
1) write the equation down
H2SO4 + KNO3 -> HNO3 + KHSO4
2) Write down how many moles of each reactant/product
H2SO4 + KNO3 -> HNO3 + KHSO4
1 1 1 1
3) Write down their atomic weights (g/mol)
H2SO4 + KNO3 -> HNO3 + KHSO4
98 101 63 136
4) For the example lets say you have 196g of H2SO4. Lets see how much KNO3 you'll need
(Write down known values, in grams)
H2SO4 + KNO3 -> HNO3 + KHSO4
196 x1 x2 x3
5) Write the proportion and solve
196 98
----- = ----
x1 101
* The ratio 98:101 is the amount of H2SO4 to KNO3
6) If you solved correctly you would have gotten 202g of KNO3 for 196g of H2SO4
* To apply to other methods make sure to match up the numerators and denominators right
196g of H2SO4 lines up with the 98g/mol of H2SO4
* To solve for other amounts of H2SO4 replace the 196 in the proportion with the grams of H2SO4 you will be using
* I write down how many moles of each because it helps on writing the proportion write. Writing the known values helps by you know what you can or need to solve for.
P.S. I am sorry if you get mad at me for this new topic because I am still new at posting here. I just wanted to make a contribution to this forum community. I hope this is a contribution and that someone finds it useful.
1) write the equation down
H2SO4 + KNO3 -> HNO3 + KHSO4
2) Write down how many moles of each reactant/product
H2SO4 + KNO3 -> HNO3 + KHSO4
1 1 1 1
3) Write down their atomic weights (g/mol)
H2SO4 + KNO3 -> HNO3 + KHSO4
98 101 63 136
4) For the example lets say you have 196g of H2SO4. Lets see how much KNO3 you'll need
(Write down known values, in grams)
H2SO4 + KNO3 -> HNO3 + KHSO4
196 x1 x2 x3
5) Write the proportion and solve
196 98
----- = ----
x1 101
* The ratio 98:101 is the amount of H2SO4 to KNO3
6) If you solved correctly you would have gotten 202g of KNO3 for 196g of H2SO4
* To apply to other methods make sure to match up the numerators and denominators right
196g of H2SO4 lines up with the 98g/mol of H2SO4
* To solve for other amounts of H2SO4 replace the 196 in the proportion with the grams of H2SO4 you will be using
* I write down how many moles of each because it helps on writing the proportion write. Writing the known values helps by you know what you can or need to solve for.
P.S. I am sorry if you get mad at me for this new topic because I am still new at posting here. I just wanted to make a contribution to this forum community. I hope this is a contribution and that someone finds it useful.