megalomania
June 26th, 2003, 03:17 PM
ST
Frequent Poster
Posts: 100
From: 000
Registered: SEP 2000
posted February 07, 2001 06:27 PM
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At what angle will you get the furthest trajectory?
I have 38 degrees imprinted in my head, which goes slightly further than 45, can someone confirm this?
endotherm
Frequent Poster
Posts: 164
From: dunno
Registered: JAN 2001
posted February 07, 2001 08:12 PM
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I am preety sure it is 45 degrees for a non rocket propelled missile, like a bullet, or spud from a spud gun
[This message has been edited by endotherm (edited February 07, 2001).]
CragHack
Frequent Poster
Posts: 606
From:
Registered: DEC 2000
posted February 07, 2001 10:03 PM
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yes, if you want to shoot something as far as it will shoot, angel it at 45 degrees.
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...Æ
BaDSeeD
Frequent Poster
Posts: 80
From: buffalo, ny
Registered: SEP 2000
posted February 08, 2001 01:50 AM
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Wrong. Wind resistance affects trajectory more than gravity. Optimal angle is 22.5 degrees.
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BaDSeeD
Knowledge is the true power, ignorrance will bring your demise.
ST
Frequent Poster
Posts: 100
From: 000
Registered: SEP 2000
posted February 08, 2001 03:00 AM
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Badseed, not that it was relevant to the question, how can you say wind resistance effects trajectory more than gravity!..
Without gravity the bullet wouldnt even come down, itll effect variance but that wasnt the question.
how did you arrive at 22.5 degrees? too shallow for me to believe.
I think there was very little difference from 38-45 but 'theoretically' 38 degrees was optimal.
Wasnt there some mortarmen in here?
Microtek
Frequent Poster
Posts: 196
From:
Registered: JAN 2001
posted February 08, 2001 05:25 AM
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Yes I used to calculate trajectories for mortars, and the truth is that air resistance does make a difference because it brakes the projectile. The optimal angle for earth-standard atmosphere is 43.5 degrees. In vacuum it would be 45.
PS. Note that air resistance will have a greater effect on small projectiles because of their relatively larger surface which gives a relatively greater drag. The 43.5 degrees are optimal for 81mm grenades which weigh 3.3 Kg, but it may not be optimal for very light projectiles.
[This message has been edited by Microtek (edited February 08, 2001).]
HMTD Factory
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Posts: 220
From:
Registered: FEB 2001
posted February 08, 2001 05:28 AM
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As far as I know .22 LR achieve it's longest
range at 25~30 degrees. (Cartridges of the World, 8th edition page 380) And that's not
45 degrees nor 38 degrees.
Projectiles lose velocity as they go, that's why ballistic coefficient(in turns affect resistance given to the bullet.) of the projectile is very important when you want to find maximum range.
Common bullets with "excellent" ballistic coefficient have bc of around only 0.500, out of perfect 1.000.
There are some dream bullets made with alloys
, long and slender, having astounding bc of 0.910. now that's something that will fly far
at 45 degrees...
Maximum range...you are talking about the maximum x-axis projection of parabolas that are distorted by loss of velocity which is distorted by the factor of current velocity.
Not very simple when you do things in earth atmosphere eh? Guess that's why people want to become astronaunts.
Frequent Poster
Posts: 100
From: 000
Registered: SEP 2000
posted February 07, 2001 06:27 PM
--------------------------------------------------------------------------------
At what angle will you get the furthest trajectory?
I have 38 degrees imprinted in my head, which goes slightly further than 45, can someone confirm this?
endotherm
Frequent Poster
Posts: 164
From: dunno
Registered: JAN 2001
posted February 07, 2001 08:12 PM
--------------------------------------------------------------------------------
I am preety sure it is 45 degrees for a non rocket propelled missile, like a bullet, or spud from a spud gun
[This message has been edited by endotherm (edited February 07, 2001).]
CragHack
Frequent Poster
Posts: 606
From:
Registered: DEC 2000
posted February 07, 2001 10:03 PM
--------------------------------------------------------------------------------
yes, if you want to shoot something as far as it will shoot, angel it at 45 degrees.
------------------
...Æ
BaDSeeD
Frequent Poster
Posts: 80
From: buffalo, ny
Registered: SEP 2000
posted February 08, 2001 01:50 AM
--------------------------------------------------------------------------------
Wrong. Wind resistance affects trajectory more than gravity. Optimal angle is 22.5 degrees.
------------------
BaDSeeD
Knowledge is the true power, ignorrance will bring your demise.
ST
Frequent Poster
Posts: 100
From: 000
Registered: SEP 2000
posted February 08, 2001 03:00 AM
--------------------------------------------------------------------------------
Badseed, not that it was relevant to the question, how can you say wind resistance effects trajectory more than gravity!..
Without gravity the bullet wouldnt even come down, itll effect variance but that wasnt the question.
how did you arrive at 22.5 degrees? too shallow for me to believe.
I think there was very little difference from 38-45 but 'theoretically' 38 degrees was optimal.
Wasnt there some mortarmen in here?
Microtek
Frequent Poster
Posts: 196
From:
Registered: JAN 2001
posted February 08, 2001 05:25 AM
--------------------------------------------------------------------------------
Yes I used to calculate trajectories for mortars, and the truth is that air resistance does make a difference because it brakes the projectile. The optimal angle for earth-standard atmosphere is 43.5 degrees. In vacuum it would be 45.
PS. Note that air resistance will have a greater effect on small projectiles because of their relatively larger surface which gives a relatively greater drag. The 43.5 degrees are optimal for 81mm grenades which weigh 3.3 Kg, but it may not be optimal for very light projectiles.
[This message has been edited by Microtek (edited February 08, 2001).]
HMTD Factory
Frequent Poster
Posts: 220
From:
Registered: FEB 2001
posted February 08, 2001 05:28 AM
--------------------------------------------------------------------------------
As far as I know .22 LR achieve it's longest
range at 25~30 degrees. (Cartridges of the World, 8th edition page 380) And that's not
45 degrees nor 38 degrees.
Projectiles lose velocity as they go, that's why ballistic coefficient(in turns affect resistance given to the bullet.) of the projectile is very important when you want to find maximum range.
Common bullets with "excellent" ballistic coefficient have bc of around only 0.500, out of perfect 1.000.
There are some dream bullets made with alloys
, long and slender, having astounding bc of 0.910. now that's something that will fly far
at 45 degrees...
Maximum range...you are talking about the maximum x-axis projection of parabolas that are distorted by loss of velocity which is distorted by the factor of current velocity.
Not very simple when you do things in earth atmosphere eh? Guess that's why people want to become astronaunts.