Setharier
November 22nd, 2008, 04:18 PM
Hopefully this hasn't been yet discussed around. I just feel I have responsibility of bringing this into knowledge due to the fact EU actually plans to limit or even partially ban commercial sale of KNO3, NH4NO3, HNO3, H2SO4, hexamine and various other general "terrograde" chemicals due to threat of terrorism. The way to obtain KNO3 from commercial dozen-fertilizers is explained in this conversation:
>> I have found a couple of methods for synthesizing
>> Potassium Nitrate from common chemicals. This method
>> relies on Calcium Nitrate (fertilizer) as the precursor
>> for making KNO3.
>>
>> The reaction is pretty simple:
>>
>> Ca(NO3)2 + K2SO4 --> 2KNO3 + CaSO4
>>
>> The molecular weight of these compounds is:
>>
>> Calcium Nitrate = Ca(NO3)2 = 164.0879
>> Calcium Sulphate = CaSO4 = 136.1416
>> Potassium Nitrate = KNO3 = 101.1032
>> Potassium Sulphate = K2SO4 = 174.2602
>>
>> The right percentage of chemicals required to balance the
>> reaction from a stoichiometricly is:
>>
>> Calcium Nitrate ................... 48.5
>> Potassium Sulphate ................ 51.5
>>
>> Which results in:
>>
>> Potassium Nitrate ................. 59.8
>> Calcium Sulphate .................. 40.2
>>
>> Assuming you start with 485 grams of Calcium Nitrate and
>> 515 grams of Potassium Sulphate, your result is approximately
>> 598 grams of Potassium Nitrate and 402 grams of Calcium
>> Sulphate. Ideally, you would do this by dissolving the
>> chemicals in distilled water and boiling to facilitate the
>> ion exchange.
>>
>> The Calcium Sulphate resultant is technically insoluble in
>> water (and becomes even more insoluble when the temperature
>> is increased). By adding distilled water to the solution you
>> can separate the Potassium Nitrate from the Calcium Sulphate
>> very easily. The solubility of Potassium Nitrate in water is
>> as follows:
>>
>> 13 g/100 ml (0 °C)
>> 32 g/100 ml (20 °C)
>> 64 g/100 ml (40 °C)
>> 110 g/100 ml (60 °C)
>> 169 g/100 ml (80 °C)
>> 246 g/100 ml (100 °C)
>>
>> For a temperature of 20C and a result of 598 grams of KNO3,
>> you would need approximately 1869 m/l of water to dissolve
>> the potassium nitrate (598g / 32 = 1869 m/l), plus a little
>> bit more for evaporation. If you heat the solution slightly,
>> you should get Potassium Nitrate dissolved in water, and
>> Calcium Sulphate should precipitate out of the solution.
>>
>> Simply siphon off the clear solution (this is the "supernatant").
>> You may even be able to filter the Calcium Sulphate from the
>> solution by pouring the solution through filter paper. Boil the
>> supernatant until you start to see the Potassium Nitrate appear
>> as surface tension on the top of the hot solution. Remove the
>> container from the heat, cool the solution to 0 C, and let the
>> KNO3 crystals precipitate out of the solution.
>>
>> You should be able to get 477 grams of pure KNO3 (calculated
>> as (1 - (13g / 246g)) x 598g KNO3 = 566g AN), with 32 grams
>> left in the solution. You can repeat this process on the
>> remaining solution to get another 30 grams of KNO3.
>> I have found a couple of methods for synthesizing
>> Potassium Nitrate from common chemicals. This method
>> relies on Calcium Nitrate (fertilizer) as the precursor
>> for making KNO3.
>>
>> The reaction is pretty simple:
>>
>> Ca(NO3)2 + K2SO4 --> 2KNO3 + CaSO4
>>
>> The molecular weight of these compounds is:
>>
>> Calcium Nitrate = Ca(NO3)2 = 164.0879
>> Calcium Sulphate = CaSO4 = 136.1416
>> Potassium Nitrate = KNO3 = 101.1032
>> Potassium Sulphate = K2SO4 = 174.2602
>>
>> The right percentage of chemicals required to balance the
>> reaction from a stoichiometricly is:
>>
>> Calcium Nitrate ................... 48.5
>> Potassium Sulphate ................ 51.5
>>
>> Which results in:
>>
>> Potassium Nitrate ................. 59.8
>> Calcium Sulphate .................. 40.2
>>
>> Assuming you start with 485 grams of Calcium Nitrate and
>> 515 grams of Potassium Sulphate, your result is approximately
>> 598 grams of Potassium Nitrate and 402 grams of Calcium
>> Sulphate. Ideally, you would do this by dissolving the
>> chemicals in distilled water and boiling to facilitate the
>> ion exchange.
>>
>> The Calcium Sulphate resultant is technically insoluble in
>> water (and becomes even more insoluble when the temperature
>> is increased). By adding distilled water to the solution you
>> can separate the Potassium Nitrate from the Calcium Sulphate
>> very easily. The solubility of Potassium Nitrate in water is
>> as follows:
>>
>> 13 g/100 ml (0 °C)
>> 32 g/100 ml (20 °C)
>> 64 g/100 ml (40 °C)
>> 110 g/100 ml (60 °C)
>> 169 g/100 ml (80 °C)
>> 246 g/100 ml (100 °C)
>>
>> For a temperature of 20C and a result of 598 grams of KNO3,
>> you would need approximately 1869 m/l of water to dissolve
>> the potassium nitrate (598g / 32 = 1869 m/l), plus a little
>> bit more for evaporation. If you heat the solution slightly,
>> you should get Potassium Nitrate dissolved in water, and
>> Calcium Sulphate should precipitate out of the solution.
>>
>> Simply siphon off the clear solution (this is the "supernatant").
>> You may even be able to filter the Calcium Sulphate from the
>> solution by pouring the solution through filter paper. Boil the
>> supernatant until you start to see the Potassium Nitrate appear
>> as surface tension on the top of the hot solution. Remove the
>> container from the heat, cool the solution to 0 C, and let the
>> KNO3 crystals precipitate out of the solution.
>>
>> You should be able to get 477 grams of pure KNO3 (calculated
>> as (1 - (13g / 246g)) x 598g KNO3 = 566g AN), with 32 grams
>> left in the solution. You can repeat this process on the
>> remaining solution to get another 30 grams of KNO3.