I got this in the mail...
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A very amateur student of chemistry, I came up with a possible idea for a total lysergic acid synthesis. I've no idea whether it would really work and I haven't the means to try, so submit my doodling to the Chemistry Archive. Perhaps some more experienced chemist will see it and work out whether there's anything good here or not.
The central idea behind this synthesis is that substituted naphthols, and 2-naphthol in particular, will react with dienophiles to form Diels-Alder adducts. I remember stumbling across a definite instance of this reaction in the literature, many years ago; as I remember, 2-naphthol was reacted with 1,2-ethylenedisulfonic acid (or an ester of that acid.)
The 1,2-ethylenedisulfonic acid here acts a synthon for acetylene--that's an important aspect of this synthesis. There may be other synthons for acetylene which will work (I vaguely remember that diethyl acetylenedicarboxylate is another such).
The presence of the nitro group in the second step, the reductive amination, is problematic. An alternative, more time-consuming procedure would be to reduce it to an amino group and then protect it by acetylation or phthalimidation, before carrying out the reductive amination.
The third step is a leap of logic. (Or of faith.) The hope is that, in the reducing, acidic workup from the ozonolysis, the nitro group will be reduced to an amino group (and then condense with the 4-formyl group to form an indole), and that simultaneously, a Knoevenagel-type condensation of the 1-formyl group closes the tetrahydropyridine ring.
I hope you pardon the very non-standard names:
1. 5-nitro-2-naphthol + acetylene (in the form of a synthon) = 1,2,4,5-tetrahydro-5-nitro-1,4-vinylene-2-naphthalenone (A)
2. (A) + ethyl 3-methylaminopropionate + reducing conditions = 2-(N-methyl-N-(3-carbethoxypropyl)amino)-1,2,4,5-tetrahydro-5-nitro-1,4-vinylenenaphthalene (B)
3. (B) + ozone, followed by zinc/acetic acid = [5-amino-2-(N-methyl-N-(3-carbethoxypropyl)amino)-1,4-diformyl-1,2,4,5-tetrahydronapthalene, intermediate] = ethyl isolysergate (C)
4. (C) + aqueous acid = ethyl lysergate.
http://rhodium.lycaeum.org