Author Topic: OCl- oxidation of 3,4-methylenedioxy-phenylalanine  (Read 2543 times)

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Bond_DoubleBond

  • Guest
OCl- oxidation of 3,4-methylenedioxy-phenylalanine
« on: May 23, 2004, 03:51:00 PM »
After some searching, swim has found that an OCl- oxidation of phenylalanine results in the aldehyde, and 3,4-methoxy-phenylalanine results in the 2-ketone.  Would an OCl- oxidation on 3,4-methylenedioxy-phenylalanine result in the ketone as well?

Aurelius

  • Guest
NO
« Reply #1 on: May 23, 2004, 06:08:00 PM »
if you did a search, you would have found the post regarding this question.
answer

Post 476895

(josef_k: "You will not get P2P from hypochlorite ...", Stimulants)

Post 108379 (missing)

(dormouse: "acetaldehyde + CH3MgBr -> Pol.  -Piglet", Novel Discourse)

shows MD-Ph-Ala and Ph-Ala degradation with OCl-

Post 303321

(kurupira: "found ref.!", Serious Chemistry)


procedure

Post 476937

(Lucid_Dreamer: "1b) (alternative) JACS 70, 3868 (1948) Distill", Stimulants)


(search terms: hypochlorite, phenylalanine) :o


Rhodium

  • Guest
Incorrect starting material
« Reply #2 on: May 23, 2004, 10:37:00 PM »
I believe that Mr. Bond is mistaken about 3,4-dimethoxyphenylalanine turning to the corresponding phenylacetone upon hypochlorite oxidation. The reaction is called "strecker degradation" and will turn any phenylalanine to its corresponding phenylacetaldehyde.

For the end product to be a phenylacetone, the starting material needs to be an alpha-methyl-phenylalanine.

Strecker Degradation of alpha-Methyl-3,4-dimethoxyphenylalanine to 3,4-dimethoxyphenylacetone

(https://www.thevespiary.org/rhodium/Rhodium/chemistry/p2p.strecker.html)


mellow

  • Guest
C-alkylate instead
« Reply #3 on: May 24, 2004, 12:40:00 PM »
I agree with Rhodium.

But if one had 3,4-methylenedioxy-phenylalanine wouldn't it be a good idea to alkylate with a methyl group at the alpha position followed by the nitrogen, decarboxylating along the way.
1) R1-CH2-CH(NH2)-COOH + EtOH  --> R1-CH2-CH(NH2)-CO.OEt (Fisher esterification, refux with 5% HCl added via gassing)
2) R1-CH2-CH(NH2)-CO.OEt + R2-CHO  -->  R1-CH2-CH(N=CH-R2)-CO.OEt
3) R1-CH2-CH(N=CH-R2)-CO.OEt + MeX  -->  R1-CH2-C(Me)(N=CH-R2)-CO.OEt  [strong basic conditions with a PTC]
4) R1-CH2-C(Me)(N=CH-R2)-CO.OEt  --> R1-CH2-C(Me)(NH2)-CO.OEt  [hydrolysis]
5) R1-CH2-C(Me)(NH2)-CO.OEt  -->  R1-CH2-C(Me)(NH2)-COOH  [hydrolysis]
6) R1-CH2-C(Me)(NH2)-COOH - CO2 -->  MDA  [decarboxylation]

R1 : 3,4-MD-phenyl-
R2 : substituted-phenyl-  [eg. para-chloro-phenyl]
X : halogen (bromide / iodide)
Me : Methyl-
Et : Ethyl-

I appreciate that it looks like a large number of reactions but these are all very high yield and quite simple.  It's an easier and higher yielding route than what you propose, which anyway, wouldn't work as you plan.