If you are resolved on doing this, there is a lot more to it than you would imagine. If you really want to try this, and do it right, you have to understand the basic properties of a phosphate solution. The H3P04 will not hydrolize the epoxide by itself, perhaps it could work but definately would not do so consistently and I will explain to you why.
Now, you say that you will attempt this by increasing the concentration to have the same percent of availiable H+ as the sulfuric. But let me ask you a question....
what are you going to increase it to, to reach this equivalent pH? The fact is that with phosphoric acid, unlike most other acids, there is no precise way of calculating this.
Orthophosphoric acid, unlike the mono or dibasic strong acids recommended for the pinacol, is a weak tribasic, it has three replacable hydrogens and can form three different salts when ionized in water.
First, the alkaline phosphate, PO
43-Second, the neutral hydrogenphosphate, HPO
42-Third, the acidic dihydrogenphosphate, H
2PO
4- (which is only a monovalent radical)
Now in addition to this the phosphate is a very strong proton acceptor, and it is hydrolized in the aqueous phase.
PO4 + H2O > HPO4 + OH
The product is an additional hydroxide ion and another hydrogen phosphate.
Now the real
bitch here is that both H2PO4 and HPO4 are amphoteric, meaning that they will react with an acid OR a base to form different salts. These reactions are based on random mathematics which keep the two competing for equilibrium. At no point in time do you know the how many moles of each salt is present, and therefore it is impossible to mathematically predetermine the precise pH. However, just for you, I pulled up a graph which 'approximates' the figures. They based it on the the Henderson-Hasselbalch equation.
http://www.sfu.ca/chemcai/AQCHEM/ABG07.html
Oh, and it gets worse. I read a report that tried to eliminate the acidic species by titration with NaOH. Unfortunatly because of the unique desire of this solution to maintain an equilibrium around the neutralization points (on the titration curve) of each of the three protons, even
LARGE variances in acid concentration will produce only very slight effects on the log concentration.
Potentiometric Titration Analysis
http://www.wku.edu/~henrich/mixedacid.pdf
A phosphate solution is acutally an organic buffering agent operating on Le Chatelier's Principle. It will try to hold the solution pH at pH 2.1±1, pH 6.7±1 and pH 12.7±1. It tends to prefer the neutral condition, however. The phosphate buffer is also important in the kidneys and urine for controlling acid base balance and regulating the concentration of Na+. In the kidneys sodium ions are retained and replaced by hydrogen ions. The pH of urine is normally 5.6 i.e. more acidic than blood plasma as a result of this process.
For those of you who are curious, the ionization constants and corresponding pK values are:
K1 = 7.5 x 10n3 pK1 = 2.13
K2 = 7.5 x 10n8 pK2 = 7.13
K3 = 4.8 x 10n13 pK3 = 12.32
So now with an understanding of the reaction I would suggest giving it a shot.
Use the graph and find out how concentrated it the solution would have to be to reach a log concentration where the pH is around 2, which is a rough estimation of a 15% conc sulfuric solution. Maybe it's more like 1.8. You should double check. But in any case keep in mind that this concentration will not make too much of a difference past a certain point.
Now check the pH, and if it isn't right don't bother trying to adjust your numbers (as I am not even sure it is volumetrically feasable to get it right), but instead titrate the solution with aq HCl until you reach the desired pH. Once you start don't stop until you reach one of the three neutralization points, as the solution will be constantly retaliating and trying to form an equalibrium.
I couldn't tell you anything about reaction times but at similar pH i'd start with similar times and then go by observation.
Then again, I might be leaving something out, or not thinking about something, so chances are this might not work at all. It is not really a good substitute in my opinion, and because of it's ionization properties it would be more trouble than it is worth.
Hell, i'll go ahead and make this little write-up complete for you. Here's the density of the solution and the maximum concentration as well, take a look.
http://www.food.us.rhodia.com/brochures/acid/page12.asp
Here's your bp/mp information if you want to try to make a saturated solution.
http://www.food.us.rhodia.com/brochures/acid/page11.asp#table4
And here is a good supplier. Hopefully no one in the stimulants forum sees this.
http://www.starchemicals.com/phosphorustechnical.htm
Oh yeah, and I almost forgot the MSDS, don't hurt yourself dude.
http://www.jtbaker.com/msds/p3973.htm
But, yeah, definately do give it a shot. Post your results to this thread.
Flip
