Author Topic: I2 tincture extraction  (Read 7721 times)

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acx01b

  • Guest
I2 tincture extraction
« on: October 14, 2004, 05:36:00 PM »
- white spirit
- H2O2 3%
- H2SO4 30%

10ml iodine tincture + 5ml H2SO4 + 0.5ml H2O/H2O2 + 5ml white spirit, mix well and organic phase will be dark coloured...


(keywords) tincture teincture extraction separation i2 diiode diode iodine iodin oxydation ki

geezmeister

  • Guest
why not make crystals?
« Reply #1 on: October 14, 2004, 06:37:00 PM »
Why not make crystals?

Have you taken a look at the stim forum faq?

Iodine

Post 109151

(Osmium: "Home-made I2", Stimulants)

Post 311336 (missing)

(geezmeister: "I2 from tincture", Stimulants)

Post 323416 (missing)

(Rhodium: "Iodine (Tincture) FAQ", Stimulants)

Post 450132

(SHORTY: "Recycling Iodine", Stimulants)

Post 463056 (missing)

(VideoEditor: "Another look at Iodine recovery...", Stimulants)

Post 496756

(elfspice: "stochiometry!", Stimulants)

Post 507866

(mr_pyrex: "Iodine from KI - Working Procedure", Stimulants)

Post 508148

(SHORTY: "Iodine from KI: This recently worked for me", Stimulants)

Post 75211 (missing)

(Stonium: "Your Iodine/Phosphorus Everything", Stimulants)


This is just one section of the faq.


acx01b

  • Guest
i didn't know that 0.5ml of 3% H2O2 could...
« Reply #2 on: October 14, 2004, 06:54:00 PM »
i didn't know that 0.5ml of 3% H2O2 could allow you to get more than 100mg of I2...

it is really not 1 mol --> 1 mol

but maybe you knew it ; )

Rhodium

  • Guest
Up to 111 mg is possible under ideal conditions
« Reply #3 on: October 15, 2004, 02:00:00 AM »
2 HI + H2O2 -> I2 + 2 H2O
H2O2 = 34 g/mol
I2 = 254 g/mol

0.5 mL * 0.03 mg/mL = 15 mg H2O2 (0.44 mmol)
0.44 mmol * 254 mg/mmol = 111 mg I2


Theoretically, 0.5 mL 3% H2O2 can precipitate 111 mg I2 from a HI solution.


acx01b

  • Guest
salut but finally I dont react H2O2 with KI...
« Reply #4 on: October 15, 2004, 05:33:00 AM »
salut, pouvez-vous m'expliquer pourquoi et comment?

but finally I dont react H2O2 with KI but with KI and I2,
what is the max concentration of I2 in a solution of KI ?
does the presence of ethanol or not changes something ?
(newbee question: why before adding H2O2 the I2 cannot go in the white spirit?)

finally i tried to add some ether and magnesium to my I2-white spirit solutin: and it looked like if there was some R-X in the white spirit ; )

merci d'avance

acx01b

  • Guest
report of what i did this morning: 5ml of...
« Reply #5 on: October 29, 2004, 01:27:00 AM »
report of what i did this morning:

5ml of iodine tincture in a test tube is mixed with some toluene.
 a mix of h2s2o8 and water is prepared (h2s2o8 reacts with water to yield h2so4 and h2o2) and is added drops by drops mixing the 2 phases in the test tube each time until the toluene is dark purple coloured.
then it is well mixed until the aqueous phase becomes completly yellow.
toluene phase is separated and is mixed in another test tube with a half concentrated solution of naoh, which is added drops by drops mixing each time until the toluene phase becomes yellow.

the aqueous phase is separated, cooled (2-3°C) and mixed in another test tube with some COLD 20% H2SO4...

the solution is filtered with a normal coffee filter and small crystals of iodines (less than 1mm) have been separated from solution... and the filtrate is yellow because of traces of iodine  (solubility of iodine in water : 300mg per L)

to use naoh and then h2so4 again should avoid most of the problems due to the presence of ethanol and not reacted KI and even H2O2 when cristalizing and filtering the iodine, and other compounds that can be founded sometimes in iodine tincture...