The Vespiary

The Hive => Newbee Forum => Topic started by: Vibrating_Lights on February 08, 2003, 07:59:00 PM

Title: Basification
Post by: Vibrating_Lights on February 08, 2003, 07:59:00 PM

How much NaOH would be needed to basify this reduction

MdP2Oxime 2275gms
35l Ethanol
683gms AL  
2gal AA  
 

Title: The needed info
Post by: Rhodium on February 08, 2003, 10:43:00 PM

The reaction goes like:

CH₃COOH + NaOH -> CH₃COONa + H₂O

The molecular weight of NaOH is 40g/mol and of acetic acid 91g/mol (its density is 1.05).

Now you easily can calculate how much you need to neutralize the solution, as the other reactants affect the pH very little.

Title: calc
Post by: Vibrating_Lights on February 09, 2003, 10:29:00 AM

NaOh=3340gms

Title: And then some more if you want to basify ...
Post by: Rhodium on February 09, 2003, 11:15:00 AM

And then some more if you want to basify rather than just neutralize. But that math is more complicated, so after adding the above amount, use pH paper to determine how much more you need to add to reach the desired pH.

Title: thanks
Post by: Vibrating_Lights on February 09, 2003, 12:09:00 PM

I'm sure i could have figured it out my self.  Thank you any way.  It is nice to have a second brain. That's gonna be a nice one,hugh.
VL_