Author Topic: to make HI or extract I, that is my question!  (Read 2136 times)

0 Members and 1 Guest are viewing this topic.

superman

  • Guest
to make HI or extract I, that is my question!
« on: April 28, 2004, 05:16:00 AM »
I was planning on making HI w/ h3po4+KI and then reacting with h3po3, but i have to switch to h2po3 for the reduction.  my question is whether i should make the HI as planned and react with h2po3 (is this possible?(rhodium i need TFSE :(  )) or would it be easier to extract the I from KI, and react it with the h3po3.

it seems to me like extracting the I would be simpler, however since i have no tfse and rhodium's site doesn't have anything that doesn't pertain to tincture i don't know...

anyone have a good method for easy extraction of I from KI?

Scottydog

  • Guest
This might help!
« Reply #1 on: April 28, 2004, 05:56:00 AM »
I wish the search engine was up and running also. I'm starting to get withdrawals. Its tough getting cut off cold turkey  ::)

When your "bookmarks" section is as long as a toilet paper roll, its easy to get by.  ;D

Here is a thread concerning KI to I2 that may help. In this thread are links to other good ones as well.

Post 493757

(mr_pyrex: "Extraction of I from KI , Rhodium", Stimulants)



SHORTY

  • Guest
Make a 10% solution
« Reply #2 on: April 28, 2004, 05:22:00 PM »
Add enough dh20 to the KI to make a 10% solution (1 liter + 100g of KI)and treat as you would tincture.

If you have the necessary setup then i would make the HI rather than extracting the I.


superman

  • Guest
I2 looks like a hell of a pain in the ass.
« Reply #3 on: April 29, 2004, 02:52:00 PM »
I2 looks like a hell of a pain in the ass.   thanks scotty for keeping me on track with the HI

interested

  • Guest
Here are some more links for obtaining I2 from
« Reply #4 on: April 29, 2004, 09:39:00 PM »
Here are some more links for obtaining I2 from KI.

Post 109151

(Osmium: "Home-made I2", Stimulants)

Post 496756

(elfspice: "stochiometry!", Stimulants)

Post 496815

(Osmium: "> I think the best way to proceed would be...", Stimulants)


It's all in the iodine section of the stimulant's FAQ.

There is a discrepency in the following links that needs to be clarified.

Rhodium answers somebody's question:

Is it possible to make HI through the reaction: HCl + NaI -> NaCl + HI

No. There are just a few methods available for making HI, and those are covered in this writeup and

https://www.thevespiary.org/rhodium/Rhodium/chemistry/hydriodic.html%5B/quote%5D%5B273747

]

And then he states in another post:
Quote
Your first scheme (with peroxide) is a bit off, you can divide all the figures with 2, and also separating the reaction in two steps, first the acidification and next the oxidation makes it easier to follow:

2 KI + 2 HCl -> 2 HI + 2 KCl
2 HI + H2O2 -> I2 + 2 H2O


Post 323629 (missing)

(Rhodium: "Good start!", Stimulants)

Again swim poses the question.  Is it possible to make HI through the reaction, HCl + KI -> KCl + HI ?  Why/Why not?




Rhodium

  • Guest
Read again
« Reply #5 on: April 29, 2004, 11:02:00 PM »
You didn't bother to check the link in

Post 323629 (missing)

(Rhodium: "Good start!", Stimulants)
which, in red typeface, is prefixed with the following text: "Edit: Read this clarification:"

It links to this post, which answers your question:

Post 459244

(Rhodium: "Behavior of ions in solution", Stimulants)