Hi,bees!
SWIM methylated tryptamine and 5meotryptamine with NaBH4 and CH2O aq.
There is description of synthesis:
The 0.8g tryptamine was dissolved in 20ml MeOH and cooled in refregerator(t minus 10C)1-2hours. Flask got from refregerator and dropped 1/10 part of 37% CH2O aq(on 1mole tryptamine take 4moles FORMALDEHYDE),shaked 1 minute and added a few (on the knife top)powder NaBH4(1g borhydride on 1g tryptamine approximatly)and vigorously shaked. When sodium borhydride was dissolved next part of 37% CH2O aq dropped and so on until all CH2O and NaBH4 was conducted to reaction(40min-1.5hours need).The temperature was keep about 5-20C(cooled in refregerator if need). The reaction mix allowed stand at room temperature some hours. Rm was diluted water, MeOH disstilled and product extracted CHCl3. Solvent removed in water bath, specific smell oil(weight 0.9g) yielded. Smoke 50mg its oil produce intense open/close eye visuals, time distortion, empathy and other strong effects. Duration up to 15min. Can anyone repit its synthesis and determine how much Dmt consist in that oil?
Sorry, my english is poor.