Hi all,
I am still experimenting with DXM because I like it, and I'm new to chemistry and the extraction from syrup is easy and a good first experiment.
My question though revolves around salt weights and dosage.
I extract the DXM by basifying, extracting with naptha, then gassing the naptha with HCL to precipitate the DXM. Works good. What I am wondering though is the amount of DXM (by weight) in the final product.
For example, lets say a 'dose' of DXM is 300mg. Given the following weights (thanks indole_amine):
dextromethorphan hydrochloride 307.86 g/mol
dextromethorphan hydrobromide 352.31 g/mol
Does that mean that to get the same amount of DXM in a 300mg dose of DXM HBR would take 262.15mg of DXM HCL?
Probably a dumb question I know, just want to make sure. (also that would explain last weekend
![Roll Eyes ::)](https://thevespiary.org/talk/Smileys/default/rolleyes.gif)
............. )
Thanks,
PB