Post 493757 (https://www.thevespiary.org/talk/index.php?topic=7764.msg49375700#msg49375700)
(mr_pyrex: "Extraction of I from KI , Rhodium", Stimulants)Post 109151 (https://www.thevespiary.org/talk/index.php?topic=7831.msg10915100#msg10915100)
(Osmium: "Home-made I2", Stimulants)Post 496756 (https://www.thevespiary.org/talk/index.php?topic=7831.msg49675600#msg49675600)
(elfspice: "stochiometry!", Stimulants)Post 496815 (https://www.thevespiary.org/talk/index.php?topic=7831.msg49681500#msg49681500)
(Osmium: "> I think the best way to proceed would be...", Stimulants)Is it possible to make HI through the reaction: HCl + NaI -> NaCl + HI
No. There are just a few methods available for making HI, and those are covered in this writeup andhttps://www.thevespiary.org/rhodium/Rhodium/chemistry/hydriodic.html%5B/quote%5D%5B273747 (https://www.thevespiary.org/rhodium/Rhodium/chemistry/hydriodic.html%5B/quote%5D%5B273747)
]
And then he states in another post:QuoteYour first scheme (with peroxide) is a bit off, you can divide all the figures with 2, and also separating the reaction in two steps, first the acidification and next the oxidation makes it easier to follow:
2 KI + 2 HCl -> 2 HI + 2 KCl
2 HI + H2O2 -> I2 + 2 H2O
Post 323629 (missing)
(Rhodium: "Good start!", Stimulants)
Again swim poses the question. Is it possible to make HI through the reaction, HCl + KI -> KCl + HI ? Why/Why not?
Post 323629 (missing)
(Rhodium: "Good start!", Stimulants) which, in red typeface, is prefixed with the following text: "Edit: Read this clarification:"Post 459244 (https://www.thevespiary.org/talk/index.php?topic=8576.msg45924400#msg45924400)
(Rhodium: "Behavior of ions in solution", Stimulants)