Basic outlined scheme is as follows:
1. Formation of the benzaldehyde from the methoxy-hydroxy benzene.
2. Conversion of aldehyde via the Clemmensen reduction into the hydroxy-methoxy-toluene.
3. Formation of the methoxy-methyl allyl-phenol ether from the hydroxy-methoxy-toluene and allylbromide.
4. Claisen rearrangement of the methoxy-methyl allyl-phenol ether into the allyl-hyroxy-methoxy-methyl-benzene.
5. Methylation of the phenolic group to form the desired allyl-dimethoxy-methyl-benzene.
Don't know if I generallized the shit out of my intermediates to where no one can imagine what they look like, but I did my best.
Rhodium, would this work?
--PK
psychokitty
Member posted 11-04-1999 06:48 PM
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This is fucked up. I was originally going to name the thread as it presently is, but then through the course of writing the contents of it, I knew that such a title made no sense so I decided to rename the thread "Synthesis of 4-Methyl-1-(2,5 dimethoxy)-allylbenzene" but I forgot to make the modification.
Sorry.
--PK
Rhodium
Administrator posted 11-06-1999 07:12 PM
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Yes, that sounds like a viable idea. Try it!
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