The Vespiary
The Hive => Chemistry Discourse => Topic started by: Bwiti on April 25, 2003, 03:55:00 PM
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I was just wondering if methylenation of allylbenzene is possible, like with catechol, or must it have two OH groups? Or, will the methylenedioxyallylbenzene have to be made from allylcatechol? :P
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Bwiti... You really should know better than to ask that! Of course you need allylcatechol, there is no way you can add oxygen groups like that to alkylbenzenes...
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Come on man!!! Do I need to take you back to school?
[allcaps]MASSIVE FLAMING[/allcaps]
Bwiti, pm me. I've got a question for you. (unrelated to the above)
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*WARNING: Question with no theoretical background whatsoever*
What if someone was to para-brominate allylbenzene, or even methamphetamine? Then couldn't the Cu powder and NaOH procedure be used on that to make a -OH substituted allyl benzene or amphetamine? Then if you were to brominate again, would it result in a single bromination right next to the -OH group? If it did, it wouldn't matter what side of the -OH it was on, and then maybe the Cu powder and NaOH again, then methylenation?
Sorry if this is completely wrong, I warned you I have no technical basis for the questions, it was just a thought.
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You cannot do that, the side-chain will react.
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Shit, I forgot about that double bond. But what about just plain old methamphetamine, or amphetamine? The Br won't replace the amine group, will it?
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Oops! Sorry about that. I shall bow-out, and do the right thing. :)
(https://www.thevespiary.org/rhodium/Rhodium/hive/hiveboard/picproxie_docs/000429331-file_sok2.jpg)