Author Topic: Crystalization yield  (Read 5301 times)

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Crystalization yield
« on: December 06, 2001, 12:01:00 AM »
Is it accurate to determine your crystalization yield by :

( weight crystals / mol. weight of crystals ) divided by

( weight freebase / mol. weight of freebase )

or does solvent, water etc. is also taken in the crystals, if so is there any accurate way to account for it ?

BTW, here I will assume mol. weight of crystals equal to mol. weight of freebase + HCl ( 36.5 )

Same for hydrated crystal form ?

If someone knows please post.