Author Topic: Question: halogenating cinnamyl alcohol  (Read 1526 times)

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java

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Question: halogenating cinnamyl alcohol
« on: June 08, 2004, 08:34:00 PM »
In halogenating the OH functional group in Cinnamyl Alcohol,   will it take preference over the double bond between C1-C2? As I want to reduce OH to CH3 without touching the double bond.  I have in mind to try the addition of a halogen and amino group at C1 C2...... java


Rhodium

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HX will add across the alkene
« Reply #1 on: June 09, 2004, 12:32:00 AM »
You can oxidize the cinnamyl alcohol to cinnamaldehyde and reduce its tosylhydrazone with NaBH4 to allylbenzene:

https://www.thevespiary.org/rhodium/Rhodium/chemistry/cinnamaldehyde.html



You cannot halogenate cinnamyl alcohol with any HX acid without touching the double bond.


Kinetic

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Cinnamyl alcohol to propenylbenzene
« Reply #2 on: June 09, 2004, 04:21:00 PM »
This contradictory response was started last night, before it became contradictory.

There are numerous literature references for the SN2 substitution of the OH in cinnamyl alcohol for chloride, bromide and iodide, using HCl, HBr and HI respectively. In fact, HI can go on to reduce the alkyl iodide to give the ever-usable propenylbenzene in one-pot.

The substitution works probably because of the conjugation of the molecule, which gives a greatly stabilised transition state for the SN2 displacement (much like the rate enhancing effects when a leaving group is alpha- to a ketone). The addition across the double bond happens at its usual (slower) rate; addition across the double bond also disrupts the favourable conjugation. Because of these effects, the -OH of cinnamyl alcohol behaves effectively like the reactive -OH of benzyl alcohol.

I would suggest adding HBr to cinnamyl alcohol to give cinnamyl bromide, followed by reduction to propenylbenzene with borohydride/PTC. Many reductions give a mixture of products (e.g. allylbenzene/propenylbenzene/propylbenzene) but with a suitable hydride nucleophile you can selectively displace the bromide with hydride (again, this may be made easier because of the conjugation stabilising the transition state).

Here are some references (some of which are available online for free). Some of them look very interesting:


Cinnamyl chloride from cinnamyl alcohol with HCl

J.Amer.Chem.Soc. 107 (7), 1985, 2033-2046
Chem.Ber., 39, 1906, 2553
Arch.Pharm.(Weinheim Ger.), 247, 1909, 349
J.Org.Chem., 42, 1977, 871-875
Justus Liebigs Ann. Chem., 479, 1930, 211, 248
J.Chem.Soc., 1941, 507, 510.


Cinnamyl chloride from cinnamyl alcohol using other sources of chloride

SOCl2, 94% yield: Org.Lett., 5 (8), 2003, 1167-1170
PPh3/trichlorocyanuric acid: Synth.Commun., 32 (17) 2002, 2691-2694
Trichlorocyanuric acid/DMF/DCM, 92% yield: Org.Lett. 4 (4), 2002, 553-556
SOCl2/benzotriazole, 100% yield: Syn.Lett., 11, 1999, 1763-1765
Potassium carbonate/chlorotrimethylsilane, 91% yield: Synthesis, 4, 1983, 314-315 [Article in German].


Cinnamyl bromide from cinnamyl alcohol with HBr

J.Amer.Chem.Soc. 38, 1916, 1076
Chem.Ber., 58, 1925, 280
J.Org.Chem., 25, 1960, 1719-1722
J.Chem.Soc., 97, 1910, 426
Chem.Ber. 39, 1906, 2553.


Cinnamyl bromide from cinnamyl alcohol using other sources of bromide

PBr3:
Chem.Ber. 43, 1910, 178
NaBr/BF3/acetonitrile (79% yield): Tetrahedron Lett., 26 (32), 1985, 3863-3866
Hexamethyldisilane/pyridinium bromide perbromide (100% yield): J.Org.Chem. 45 (9), 1980, 1638-1639
Chlorotrimethylsilane/lithium bromide (93% yield): J.Org.Chem., 45 (9), 1980, 1638-1639.


Cinnamyl iodide from cinnamyl alcohol with HI

Justus Liebigs Ann. Chem. 479, 1930, 211, 248.


Cinnamyl alcohol to propenylbenzene with HI

Chem.Ber., 11, 1878, 671.


Reduction of cinnamyl bromide to propenylbenzene

NaBH4/PTC, 80% yield:
J.Org.Chem., 46 (19), 1981, 3909-3911
Lithium tri-sec butyl borohydride, 99% yield: Bull.Chem.Soc.Jpn., 58 (2), 1985, 789-790
Zn(BH4)2, 60% yield: Angew.Chem., 95 (7), 1983, 568-569 [Article in German]
LiAlH(i-Bu)2(n-Bu), 95% yield: J.Org.Chem. 49 (10), 1984, 1717-1724.

java

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Question: halogenating cinnamyl alcohol
« Reply #3 on: June 09, 2004, 05:35:00 PM »
Rhodium... thanks for the info on going to the allylbenzene from the OH and the many other references and comments you've been providing, they are most helpful in teach me good chemistry.
 

Kinetic  thanks for the info as I see it I have a good way to go to the CH3 and also to a CX from the OH. As I 've bee looking at the dialkylamino -chloro addition to the non conjugated cinnamyl chloride

https://www.thevespiary.org/rhodium/Rhodium/pdf/archive/vinylic.aminochlorination.pdf

  , for which I feel the chlorine can be removed with hydrogenation and end up with desired product ,except a dimethylamine as oppose to a methylamine on the C2.


Saludos, from Latin America....java