Author Topic: methoxyacetyl chloride  (Read 2672 times)

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Cyrax

  • Guest
methoxyacetyl chloride
« on: June 06, 2002, 12:09:00 AM »
Is it suspicious to buy methoxyacetyl chloride? Is it a watched chemical?


Rhodium

  • Guest
I'd say that is obscure enough to be safe.
« Reply #1 on: June 06, 2002, 12:36:00 AM »
I'd say that is obscure enough to be safe.

PrimoPyro

  • Guest
Curious
« Reply #2 on: June 06, 2002, 02:49:00 AM »
Methoxyacetyl chloride...

CH3-O-CH2-CO-Cl correct?

What use would this have clandestinely? Just curious.

                                                  PrimoPyro

Cyrax

  • Guest
Well, you can use it instead of propionyl ...
« Reply #3 on: June 06, 2002, 01:39:00 PM »
Well, you can use it instead of propionyl chloride or propionic anhydride to acylate 1-phenethyl-4-(N-phenylamino)-piperidine to get a nice fentanyl analog with an ED50 of 0.08 mg / kg.  Propionyl chloride is suspicious (right?), so I think this is a good alternative.

Or you can use 2-furoyl chloride to the amine.  That compound will certainly not be suspicious.  Then the ED50 is 0.02 mg / kg.

Rhodium

  • Guest
Fentanalogs
« Reply #4 on: June 06, 2002, 01:44:00 PM »
Cyrax: Very interesting! Refs?

Nemo_Tenetur

  • Guest
... and bypass some analogue laws !
« Reply #5 on: June 06, 2002, 01:45:00 PM »
Very good idea!
Although somewhat weaker, you can get around U.K. generic definition (and maybe same in some other countries) ;)

Cyrax

  • Guest
Check it out: US patent 4584303.
« Reply #6 on: June 06, 2002, 06:17:00 PM »
Check it out: US patent 4584303.  You will find a real treasure of fentanyl analogs.  It is one of the best fentanyl patents I have read. 

Too weak: I think it is strong enough to not kill yourself during the synthesis.  If you want a stronger compound: simply use o-fluoroaniline instead of aniline.  Then the ED50 will be 0.0077 mg / kg.  But I forsee that the yield of the acylation will be lower, since that lovely little fluorine atom will suck the free electron pair of the nitrogen into the aryl ring  :)  (resonance)