This post refers to the synthesis of MDA which can be found on page 79 of Psychedelic Chemistry, which was first published in Chemical Abstracts 52, 11965c (1958).
Now I have a clear understanding the steps and factors that need to be considered upto the formation of MDP-2P - top marks for the forum and Rhodium.ws
I have a few concerns that I would like to clarify before I put valuable resources to work
This is an extract that I will ask a few questions in relation to and would be most grateful if the more experienced bees could give me a few tips or advice:
Add 23g 3,4-methylenedioxyphenylacetone to 65g HCONH2 (formamide)and heat at 190 deg for five hours.
Fine.
Cool, add 100ml H20, extract with C6H6 (benzene) and evaporate in vacuum the extract.
H20 to remove excess formamide I'm assuming - is it not better to use 3x50ml? - it is after all quite nasty stuff.
Do I use separatory funnel - rid the mixture of the bulk of the water/formamide and then extact the free base intermediate with benzene/toluene and evap under vacuum to separate the FB and solvent?
Add 8ml MeOH (methyl alcohol -- methanol) and 75ml 15% HCl to residue, heat on water bath two hours and extract in vacuum (or basify with KOH and extract the oil with benzene and dry, evaporate in vacuum) to get 11.7 g 3,4-methylenedioxyamphetamine (MDA).
So on the water bath do I heat to 100C and then strip the excess water/MeOH in the vacuum to leave the FB - or strip the water and then distill the FB?
Then finally, does the reaction with the HCL and MeOH - form hydrochloride salt or is it an intermediate to the FB? Will I need to gas in other words?
Help would be appreciated.
I have looked at thoroughly and could not find a cleaner presentation of the mechanism/reaction.
A step by step account would go along way
cheers