In this (https://www.thevespiary.org/rhodium/Rhodium/chemistry/para-fluoro-4-mar.html)
(https://www.thevespiary.org/rhodium/Rhodium/chemistry/para-fluoro-4-mar.html) synthesis, Bandil uses para-fluorobenzaldehyde and condenses it with nitroethane to get the nitroalcohol.
In my experience the nitroalcohol is hard to isolate, since it is easily dehydrated to the nitrostyrene thanks to conjugation. It is obvious that the fluorine atom affects the molecule in such a way that it is possible to isolate the alcohol instead of the styrene.
What I need to know is whether it is possible to react regular benzaldehyde with nitroethane and stop at the nitroalcohol. If one does not use acetic acid as solvent, and keep the entire isolation process if not basic then at least neutral (not acidic), do you think this could be done?
Thanks in advance.
Read this (https://www.thevespiary.org/rhodium/Rhodium/chemistry/phenyl-2-nitropropanol.html)
(https://www.thevespiary.org/rhodium/Rhodium/chemistry/phenyl-2-nitropropanol.html) patent on forming the correct nitroalcohol.
Use the same procedure, neutralize the trialkylamine catalyst with dilute acetic acid, and extract the nitroalcohol. Carry on directly with the reduction, using either Pd/C CTH or Zn/KCOOH nitro reduction. Any benzaldehyde left in the nitroalcohol and reduced aminoalcohol, will be removed in an acid/base extraction.
I do not see enormous obstacles in this synthesis, although i do not have first hand experience (other than the fluorinated version of course)!
Regards
Bandil
cfr.: Post 505289 (https://www.thevespiary.org/talk/index.php?topic=7031.msg50528900#msg50528900)
(Megatherium: "Stoichiometry of ammonium formate reductions", Chemistry Discourse)