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The Hive => Methods Discourse => Topic started by: Vibrating_Lights on August 26, 2003, 05:33:00 PM

Title: SYNTHESIS of 3Br-Methcathinone NAs assay
Post by: Vibrating_Lights on August 26, 2003, 05:33:00 PM

All reagents were lab Grade including D-Ephedrine.

22 Gms Ephedrine Hcl was placed into a 1l RBf in a water bath.
A standard jones reagent was prepared.
.15 mole Jones reagent employed. This was added.  THe SOlution began to reflux it self after about an hour.  WHEN it slowed low heat was applied.  Reaction was followed with TLC to COompleteion.  6 Hrs.  The Rxn was allowed to coll and then was basified with SAturated KCO3. SOlution was vac filtered to remove percipitated Cromium. FIlter was washed with EtAcOH. THe FIlterate was extracted WIth  EtAcOH the FIlterates COmbined and solvent was removed on a rotovap.  Product verafied WIth NMR

Yeild 21gms D-Methcathinone

20 gms Methcathinone was DIssolved in 200Ml AA that contained .1M Bromine.
This was stirred FOr 4 Hrs. 

Rxn was basified and extracted into 200ml EtACOH.  This was washed with Na2SO4.  then BICarbonate.

THe EtAcOH was dried with NaSO4 and added to C.HCL iN acetone.
Yeild  17gms
3-Br-Methcathinone.  25-30MGS +++
NMR PIc Coming
COmments AND MANY MORE FUN HIGH POTENCY SYNTHS TO COME
LOve
Ya VL_

Title: 3-Br or 4-Br ??
Post by: Vitus_Verdegast on August 26, 2003, 06:20:00 PM

Question may sound abit stupid  :-[  :-[  but...

Is bromination of methcathinone meta-directing because of it beta-carbonyl group, in other words does the 2-aminopropan-1-one sidechain deactivate the benzene ring?

I thought that activating groups generally win out over deactivating groups.

Title: yes
Post by: Vibrating_Lights on August 26, 2003, 06:53:00 PM

yes.  the ketone deactivates the ring.  If you wanted to make 4 Br Methcathinone you would have to start by brominating the ephedrine FIrst then oxidise.

Http://www.geocities.com/axelfj/research.html (http://Http://www.geocities.com/axelfj/research.html)

Title: Are you sure?
Post by: dennis_pro on September 03, 2003, 07:49:00 PM

Are you sure that you've obtained a 3-Br-methcatinone? I'm think that bromine will attack near-ketone atom first, producing bromoketone (like bromacetone, for example), i.e. Ph-C(=O)-C(Br)(CH3)(NHCH3) or not? Did you make any analysis of your compound?

Title: Maybe a little of topic
Post by: Blind_Angel on September 03, 2003, 08:49:00 PM

But, can someone explain me why adding a bromine on the 4th/3rd position of a ring make the honey more potent? (or refer me to a link)

Title: wtf???
Post by: hypo on September 04, 2003, 12:17:00 AM

> But, can someone explain me why adding a bromine on the 4th/3rd position
> of a ring make the honey more potent? (or refer me to a link)

what the fuck are you talking about?? 2C-H? 2,5-DMA?

Title: alpha bromo ketone VERY unstable
Post by: Pimpo on September 04, 2003, 11:19:00 AM

Hi dennis_pro, indeed it would be a good idea to clearly establish the identity of the product. I just wanted to point out that the alpha-substitution product Ph-C(=O)-C(Br)(CH3)(NHCH3) you proposed would be highly unstable (bromo- and methylamino-groups on the same carbon). I guess it would eliminate HBr and form the imine Ph-C(=O)-C(CH3)(=NCH3), which again looks pretty unstable and might react to god knows what. I could imagine that A/B extraction does get rid of it, if it was formed. Just some speculation.