"Experiment 19: Amides"
"Introduction. Another important derivative of carboxylic acids is the amide group, formally a condensation product of a carboxylic acid and an amine.
"Because amides are the most stable and least reactive of the family of carboxylic acid derivatives, they can be produced by the reaction of amines with any of the more reactive relatives: (a) acid chlorides (b) anhydrides, or (c) esters, OR [emphasis added] EVEN (D) FROM THE CARBOXYLIC ACID ITSELF, USING HIGHER TEMPERATURES [greater than 200 degrees Centigrade]. This chapter will present examples of several of these methods.
"(a) R-CO-Cl + R'-NH2 --> R-CO-NH-R' + HCl
(b) R-CO-O-CO-R + R'-NH2 --> R-CO-NH-R' + R-COOH
(c) R-CO-O-R + R'-NH2 --> R-CO-NH-R' + R-OH
(d) R-CO-OH + R-NH2 --> R-CO-NH-R' + H2O"
If you had ever had both METH-LAD and ETH-LAD, then I think that you would also probably be able to tell the difference.
As for acid being a "dirty" drug, well everyman is entitled to his opinion, and different drugs affect different people's bodies in different ways. See also set and setting.
The fact that the hydroxide ion is a poor leaving group is the reason that higher temperatures must be used in example (d) from above, and it is also the reason that yields suffer when compared with method (a) from above. Consult some organic chemistry textbooks and/or lab manuals if you are still confused.
Oh yeah, I've tried 2-MeO-3,4-MDA as well while on acid, and it was a nightmare. How do I know for sure what they were? I don't, but good luck convincing me otherwise.
Just my 888 cents.