If the reduction of an azide with SnCl2 were to form Sn-NH2 complexes, what would it entail to eliminate these complexes and free up the amine for extraction from the reaction mixture?
Here is what little I could find after sifting through several hundred posts:
In cases when the metal ion forms stable amine complexes which make ? quantitative precipitation difficult, the precipitation may be carried out with ammonium acetate or tetramethylammonium hydroxide solutions (22). In addition to these agents and the various alkali metal hydroxides, active MgO and alkaline earth hydroxides may also be used as precipitants.
Sodium borohydride enables manufacturers to meet the most stringent effluent limits, and to precipitate metals in their elemental form (rather than metal complexes)
If you a royal-blue Zn-NHCH3 complex, the zinc ions must be reduced out of solution.
That is Zn+2 + 2e ==>> Zn (s)
This is done using Mg metal, or electrochemically.
So: Is it possible to break up these complexes using Mg, though the post this came from is on the subject of methylamine? Or perhaps (doubtfully) NaBH4?