The Vespiary

The Hive => Novel Discourse => Topic started by: psycosmo on December 23, 2001, 02:44:00 PM

Title: 3,4,5 trimethoxy phenylacetic(or propinoic) acid
Post by: psycosmo on December 23, 2001, 02:44:00 PM
I had an Idea about how to make 3,4,5 phenyl acetic or phenyl propinoic acid from eugenol.

1) Treat Methyleugenol with KMnO4 (for the acetic acid) or H20, H202 and NaOH then KMnO4 (for the propinoic acid)

2) Now since that COOH is meta- directing chlorination or bromination of the benzene ring with, say FeCl3 and Br2 should should set us up for 3,4,5 trimethoxy formation.

3) To do this, treat with NaOh, then MeI, which I think should form the 3rd methoxy group.

Where one would go from this I don't know, forming amides from carboxylic acids seems to be either highly toxic (such as the thionyl chloride method) or highly ineffecient (heating with ammonia method).
Title: Re: 3,4,5 trimethoxy phenylacetic(or propinoic) acid
Post by: PrimoPyro on December 23, 2001, 06:45:00 PM
Urea readily donates an amide group to carboxyls, itself then decomposing to amonia gas and carbon dioxide.

Urea is carbamide: (NH2)C=O

                                                PrimoPyro

Vivent Longtemps la Ruche!
Title: Re: 3,4,5 trimethoxy phenylacetic(or propinoic) acid
Post by: Rhodium on December 25, 2001, 12:15:00 PM
Only COOH directly attached to the ring is meta-directing, not if it is a phenylacetic or phenylpropionic acid. You would get ortho-substitution with the bromine next to the side chain.