Actually that's interesting and clears a lot up for me. This was also a major point of one source I read, however, not really to be a concern as 1-phenyl-2-propanol is a secondary alcohol, is it not? We're not really trying to produce a aldehyde here as one might think if he or she were to read about the Fenton specifically. This reaction was originally performed with primaries in mind, but H2O2 is great for secondaries as well. Secondaries will not form aldehydes or carboxyls in the presence of an oxygen source, to my knowledge, they should form ketones. Which is what we want. Quoting an old high school chemistry book, "The middle [2 position] carbon in 2-propanol has an oxidation number of 0. In propanone, it has an oxidation number of +2, an increase of 2. Hence, 2-propanol is being oxidized to propanone", Chemistry: The Study of Matter, 1983, Allyn and Bacon, p. 613. Sorry to bust out the high school chem, but that's all I had on hand. It would be impossible to form aldehydes or carboxyl groups, which generlly form out of aldehydes. Thanks for the help. I now understand what was being said and would like to amend my answer to say yes, it is a legitimate concern with primaries, but not with 1-phenyl-2-propanol.
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