If anyone has done an oxone rxn and was checking to see if the colors were right then here you go.
https://www.thevespiary.org/rhodium/Rhodium/chemistry/2cb.large-scale.bromination.html (https://www.thevespiary.org/rhodium/Rhodium/chemistry/2cb.large-scale.bromination.html)
Even though that was 2C-B synthesis from 2C-H the
color of the reaction is what intrigued me about how similar it is to the unbuffered and buffered oxone rxn.
Fig1. The color of the
unbuffered oxone run. It produced glycol but after hydrolysis with 15% H
2SO
4 it produces ketone.
https://www.thevespiary.org/rhodium/Rhodium/chemistry/pictures/2cb-1.gif (https://www.thevespiary.org/rhodium/Rhodium/chemistry/pictures/2cb-1.gif)
Fig2. The overall reaction looks similar to the
buffered oxone rxn after adding some NaHCO3. This produced epoxide and after hydrolysis with 15% H
2SO
4 it produced ketone.
https://www.thevespiary.org/rhodium/Rhodium/chemistry/pictures/2cb-2.gif (https://www.thevespiary.org/rhodium/Rhodium/chemistry/pictures/2cb-2.gif)
Hell fucking Yeah. 2-cb is a far stretch from oxone. HeeHaw. Someone is going to loose their mind. good job
If the 2C-H.HCl is 99.7 % or so, then why is it yellow ? I though 2C-H freebase would be colourless like safrole.
A miniscule amount of the 2C-H decomposes upon treatment with aqueous sodium hydroxide (only a fraction of 1%) creating highly colored impurities (for example, demethylated 2C-H is a quinoid substance, both prone to di/polymerization and definitely highly colored). It does not take much impurities to create a golden color like the above - only freshly distilled phenethylamines are truly colorless.