I can only think of HI(aq), PI
3, (CH
3)
3Si-I and possibly PPh
3/I
2 as being viable iodination reagents.
NaBH
4 in diglyme (yes, only in that solvent) will also reduce iodides to the hydrocarbon.
Selective Reductions. XI. The Reaction of Sodium Borohydride with Alkyl Halides under Solvolytic Conditions.Harold M. Bell and Herbert C. BrownJ. Am. Chem. Soc. 88, 1473-1477 (1966)
(
https://www.thevespiary.org/rhodium/Rhodium/pdf/nabh4-diglyme.dehalogenation.pdf)
AbstractIn nonionizing solvents, secondary and tertiary alkyl halides react with sodium borohydride only slowly, in many cases yielding the olefin, rather than the desired saturated hydrocarbon. However, the addition of water to produce typical solvolyzing conditions brings about a rapid reaction, providing the corresponding hydrocarbon in good yield, along with the concomitant formation of the alcohol and the olefin as the usual solvolytic products. Evidence is presented which indicates that the mechanism of the reduction involves the trapping of the intermediate carbonium ions formed in the solvolysis. Consequently, the reaction should be useful, both synthetically, to convert reactive alkyl halides and their derivatives to the corresponding hydrocarbons, and mechanistically, to trap carbonium ions in investigations of their nature. A number of synthetic applications is described.