Here is i think the lowdown on the steroisomerism shit.
I have the ref rhodium posted.
And he is correct about dimethyl being the compound with a n methyl group as ephedrine. How ever the steroisomerism should be (R,S) with ephedrine and (R,R) with pseudo, I THINK.
However I would make very sure before tasteing this compound. Because the (S,S)dimethyl aminorex can easily produce fatal seziures, the article says!!! Would pseudoephedrine, which is (1R,2R)-(-)-Pseudoephedrine, produce the (S,S)dimethyl aminorex or (R,R)dimethyl aminorex?
In other words I would maybe only try this with ephedrine since it is (1R,2S)-(-)-Ephedrine and would almost surely produce a (R,S)dimethyl aminorex.
Anyone a sterochemisty wizz?
left handed or right handed and all that bullshit
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