Greetings-
I've been looking around at all of the published methadone synthesis that are about, which of course methadone is extremely well documented. So I started poking around the opioids that were similar to methadone. Funny enough, I can't find a complete reaction scheme for dipipanone anywhere. I've checked in "Opioid Analgesics" by Paffit, as well as Paul Jansens seminal text on the subject. All of these basically just say to do the same methadone synthesis but sub-out 2-dimethylaminoethyl chloride instead of 2-dimethylaminoisopropyl chloride. Anyways, my actual question is what are the intermediate aminonitriles formed by this reaction? In the case of methadone, you have a high melting and low melting nitrile, and the low melting will recrystallize from cold hexane first. Any idea if 2 aminonitriles are formed with dipipanone synth? Also, is one the useful nitrile and the other not, or can they both, with the help of grignard, create the isomers of dipipanone? Also, if one is not useful, what is the standard method of separation? Is it similar to the cold hexane crystallization (and which one is the useful product, the initial crystallizing solid, or the one that crystallizes last)? Thanks for your help- just some scholarly intrest
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A little update- I found an article from the Royal Chemistry Society ("Search for New Analgesics, Part IV, Variations in the Basic Side-chain of Amidone (w/ a Note on Some Pharmacological Results)", Ofner and Walton, RCS 2158, 1950) that has the original synthesis included (as well as many other similar opiods). It's a fantastic article- if anyone is interested in a copy, please let me know. The answer to my question is that yes, there are 2 different aminonitrile products. And yes, the active aminonitrile is crystallized from hexane (@ 0 deg C) as the second product (in basic form) and as the first product (as a halide salt). The conversion with grignard is not as easy as methadone, thought, because of an intermitent ketimine. Apparently prolonged acid hydrolysis is
needed. I would still appreciate any practical advice or thoughts on this. Thanks!
-bluealcoholflame
I've been looking around at all of the published methadone synthesis that are about, which of course methadone is extremely well documented. So I started poking around the opioids that were similar to methadone. Funny enough, I can't find a complete reaction scheme for dipipanone anywhere. I've checked in "Opioid Analgesics" by Paffit, as well as Paul Jansens seminal text on the subject. All of these basically just say to do the same methadone synthesis but sub-out 2-dimethylaminoethyl chloride instead of 2-dimethylaminoisopropyl chloride. Anyways, my actual question is what are the intermediate aminonitriles formed by this reaction? In the case of methadone, you have a high melting and low melting nitrile, and the low melting will recrystallize from cold hexane first. Any idea if 2 aminonitriles are formed with dipipanone synth? Also, is one the useful nitrile and the other not, or can they both, with the help of grignard, create the isomers of dipipanone? Also, if one is not useful, what is the standard method of separation? Is it similar to the cold hexane crystallization (and which one is the useful product, the initial crystallizing solid, or the one that crystallizes last)? Thanks for your help- just some scholarly intrest
-A little update- I found an article from the Royal Chemistry Society ("Search for New Analgesics, Part IV, Variations in the Basic Side-chain of Amidone (w/ a Note on Some Pharmacological Results)", Ofner and Walton, RCS 2158, 1950) that has the original synthesis included (as well as many other similar opiods). It's a fantastic article- if anyone is interested in a copy, please let me know. The answer to my question is that yes, there are 2 different aminonitrile products. And yes, the active aminonitrile is crystallized from hexane (@ 0 deg C) as the second product (in basic form) and as the first product (as a halide salt). The conversion with grignard is not as easy as methadone, thought, because of an intermitent ketimine. Apparently prolonged acid hydrolysis is
needed. I would still appreciate any practical advice or thoughts on this. Thanks!
-bluealcoholflame


