Reduction of Nitroalkenes to the corresponding Nitroalkanes is carried out by directly combining the Nitroalkene with a 1.1 molar equivalent of Hantzsch ester, Diethyl 1,4-dihydro-2,6-dimethyl-3,5-pyridinedicarboxylate,CAS 1149-23-1, at 100°C and letting the two react for 12 hours. Yield: 84%
What confuses me: The Hantzsch ester schould be a solid at this temperature, so basically they form a suspension of it in molten nitroalkene?
From what I read about the Hantzsch compound, making it yourself should not be too complicated, refluxing ethylacetoacetate, formaldehyde and ammonium acetate in water for 2 hrs, then adding FeCl3 and reflux 1hr more.
But supplier prices for it are quite high, so there will certainly be a twist with this method somewhere.
Thoughts about this anyone?
What confuses me: The Hantzsch ester schould be a solid at this temperature, so basically they form a suspension of it in molten nitroalkene?
From what I read about the Hantzsch compound, making it yourself should not be too complicated, refluxing ethylacetoacetate, formaldehyde and ammonium acetate in water for 2 hrs, then adding FeCl3 and reflux 1hr more.
But supplier prices for it are quite high, so there will certainly be a twist with this method somewhere.
Thoughts about this anyone?

