http://www.erowid.org/archive/rhodium/chemistry/quaalude.cheapskate.html

this is essentially the same as above, but uses polyphosphoric acid to bind the water instead of just evaporating it. Put 20 grams of polyphosphoric acid in a rb flask and begin warming it. This is not as easy as it sounds. Polyphosphoric acid is very viscous and hard to pour.

http://www.erowid.org/archive/rhodium/chemistry/quaalude.html

7g Anthranilic Acid, 5ml o-Toluidine and 4 ml glacial acetic acid was mixed in a round-bottomed flask. To this mixture was slowly added 40-50 grams of polyphosphoric acid, and the mixture was heated during 20-30 minutes to 140-160°C. After this, the mixture was heated to 180°C for 10 minutes, then cooled and poured in 150-200ml water, and neutralized with 20% Na2CO3 solution. Methanol was added until a lasting turbidity became present in the solution, and after one hour, the free base Methaqualone precipitated, mp 111-113°C, and was once more recrystallized in this fashion, mp 113-115°C. Yield 55%.

Ref: Klosa, Josef. Notiz über Eine einfache Synthese von 2,3-substituierten Chinazolon-(4)-derivaten. Journal für Praktische Chemie, Vol.20, Issue 5-6, p.283-284,1963.

A friend wants to make quaaludes using the Klosa ppa method, he have P4O10 and H3PO4 85% BUT dont know how to work the ratios. What he wants is a polyphosphoric like the one in cheapskate method, very viscous liquid, not a solid (pyro?).


P4O10 + 6 H2O --> 4 H3PO4
283,89g + 108,09g  392g

39,39g P4010 + 15g H2O --> 54,39g H3PO4

85g+54,39g=139,39g H3PO4  (100% H3PO4?)

Polyphosphoric search on sigma returnes:

- ?83% phosphate (as P2O5) basis
- reagent grade, 115% H3PO4 basis
- ~105% H3PO4 basis 

All with mp 16C bp 300C d 2,060g in the MSDS's.

He just wants aproximately 100g PPA from 105 to 115% H3PO4.